在MySQL中，检查下面雇员表中的数据：
last_name department_id salary
ALLEN 10 3000
MILLER 20 1500
King 20 2200
Davis 30 5000
下面哪个子查询能恰当执行？( )
SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);
SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);
SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);
SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);
SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));
