<p> 给出如下代码<br/> import random as ran<br/> listV = []<br/> ran.seed(100)for i in range(10):<br/> i = ran.randint(100,999)<br/> listV.append(i)<br/> 以下选项中能输出随机列表元素最大值的是( )</p>
<p> print(listV.max())</p>
<p> print(listV.pop(i))</p>
<p> print(max(listV))</p>
<p> print(listV.reverse(i))</p>
